The length of a rectangle is 6 cm more than the breadth. If the perimeter of the rectangle is 80, find the length and breadth of the rectangle
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Answered by
5
Let the breadth be x.
Length = x + 6
Perimeter = 80
Perimeter = 2 ( l + b)
80= 2 ( x +6 + x)
80 = 2 ( 2x + 6)
80 = 4x + 12
80 - 12 = 4x
68/4 = x
x = 17
So,breadth = 17
length = 17 + 6 = 23
Length = x + 6
Perimeter = 80
Perimeter = 2 ( l + b)
80= 2 ( x +6 + x)
80 = 2 ( 2x + 6)
80 = 4x + 12
80 - 12 = 4x
68/4 = x
x = 17
So,breadth = 17
length = 17 + 6 = 23
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Answered by
1
Let the breadth be x, then length be x+6.
Perimeter= 80 cm
2(l+b)=80
2(x+6+x)=80
2(2x+6)=80
2x+6=40
2x=34
x=17
So, Breadth is 17 cm and Length is 23 cm.
Perimeter= 80 cm
2(l+b)=80
2(x+6+x)=80
2(2x+6)=80
2x+6=40
2x=34
x=17
So, Breadth is 17 cm and Length is 23 cm.
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