Question

the length of a rectangle is 6 less than twice its breadth if the perimeter of the rectangle is 54 find its length and breadth ​

Answer 1

ANSWER:-

Given:

The length of a rectangle is 6 less than twice its breadth if the perimeter of the rectangle is 54.

To find:

Find its length & breadth.

Solution:

⚫Let breadth be x

⚫Let length of rectangle= 2x -6

⚫Perimeter of rectangle= 54.

Therefore,

We know that, perimeter of rectangle;

=) 2(length+breadth)

So,

=) 2(2x-6 + x) = 54

=) 2(3x -6) = 54

=) 6x -12 = 54

=) 6x = 54 +12

=) 6x = 66

=) x = 66/6

=) x = 11

Thus,

Breadth,x = 11

Length, 2x -6 = 2×11-6= 22 -6 = 16

Hope it helps ☺️

Answer 2

Answer:

The Length is 16 units and the Breadth is 11 units.

Step-by-step explanation:

Given :

Length of the Rectangle = 6 less than twice its breadth

Perimeter of the Rectangle = 54

To find :

Length and Breadth of the Rectangle

Solution :

Let the -

• Breadth be as x
• Length be as (2x - 6)

★ Perimeter = $\boxed{\sf{2(Length + Breadth)}}$

$\sf{\implies} \:2(2x - 6 +x) = 54 \\ \sf{\implies} \:2x - 6 + x = 54 \div 2 \\ \sf{\implies} \:3x - 6 = 33 \\ \sf{\implies} \:3x = 27 + 6 \\ \sf{\implies} \:\sf{\implies} \:3x = 33 \\ \sf{\implies} \:x = \frac{33}{3} \\\sf{\implies} \: x = 11$

Breadth = 11 units

$\rule{300}{1.5}$

Length =

$\sf{\implies} \:2x - 6 \\ \sf{\implies} \:2(11) - 6 \\ \sf{\implies} \:22 - 6 \\ \sf{\implies} \:16$

Length = 16 units

$\therefore$ The Length is 16 units and the Breadth is 11 units.

$\rule{300}{1.5}$

Verification :-

$\sf{\implies}\:2(16+11)=54 \\ \sf{\implies}\:32+22=54 \\ \sf{\implies}\: 54 = 54$

$\therefore$ The Length is 16 units and the Breadth is 11 units.