Math, asked by devanshdwivedi79, 10 months ago

the length of a rectangle is 6 metre less than the twice of its breadth if the perimeter of a rectangle is 54 metre find its length and breadth​

Answers

Answered by rockykaboom
7

Answer:  11

Step-by-step explanation:

perimeter of ractangle = 2(L+B)

let B=X

then L=2x-6

so, 2(x+2x-6)=54

=2x+4x-12=54

=6x=54+12

=x=66/6

=x=11

Answered by Shreyanshijaiswal81
0

ANSWER:

Given:

The length of a rectangle is 6 less than twice its breadth if the perimeter of the rectangle is 54.

To find:

Find its length & breadth.

Solution

Let breadth be x

Let length of rectangle= 2x -6

Perimeter of rectangle= 54.

Therefore,

We know that, perimeter of rectangle

=) 2(length+breadth)

So,

=) 2(2x-6 + x) = 54

=) 2(3x -6) = 54

=) 6x -12 = 54

=) 6x = 54 +12

=) 6x = 66

=) x = 66/6

=) x = 11

Thus,

Breadth,x = 11

Length, 2x -6 = 2x11-6= 22 -6 = 16

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