Question

The length of a rectangle is 6 metres more than its breadth. the perimeter of the rectangle is 60 metres . find the length and breadth of the rectangle. ​​

Answer 1

Answer:

Question:

The length of a rectangle is 6 metres more than its breadth. the perimeter of the rectangle is 60 metres . find the length and breadth of the rectangle.

To find:

• Length
• Breadth

Given:

• length of a rectangle is 6 metres more than its breadth
• perimeter = 60 m

Let:

• breadth = x
• Length =6+x

Answer:

We know:

Perimeter = 2(L+B)

by using this formula we can find value of x.

$: \implies \sf60 = 2(x + x + 6)$

$: \implies \sf \dfrac{60}{2} = (x + x + 6)$

$: \implies \sf \dfrac{ {\cancel{60}}^{ \: 30} }{ {\cancel{2}}^{ \: 1}} = (x + x + 6)$

$: \implies \sf 30 = (x + x + 6)$

$: \implies \sf 30 = (2x + 6)$

$: \implies \sf 24 = 2x$

$\begin{gathered} : \implies \sf x = \frac{24}{2} \\ \end{gathered}$

$\begin{gathered} : \implies \sf x = \frac{ {\cancel{24}}^{ \: 12} }{ {\cancel{2}}^{ \: 1} } \\ \end{gathered}$

$:\implies \star \boxed{ \sf x = 12} \star$

Let's Verify whether value of x is correct or not

$: \implies \sf60 = 2(x + x + 6)$

insert Value of x

$: \implies \sf60 = 2(12 + 12+ 6)$

$: \implies \sf60 = 2(30)$

$: \implies \star \boxed{ \sf60 = 60} \star$

$\large \dag \bigg( \large \sf{}LHS = RHS \bigg) \dag$

Hence verified!

First let's find value of length :

• Length = 6+x
• Length =6+12
• Length = 18cm.

Now Let's find value of breadth:

• Breadth = x
• Breadth = 12cm.