The length of a rectangle is 60% more than its breadth. what will be the respective ratio of the area of the rectangle to that of a square whose side is equal to the breadth of the rectangle ? 7 : 4 8 : 5 17 : 10 9 : 5 6 : 5 not answered
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let the breadth be b
length of rectangle=b+60%of b=160/100×b
area of rectangle=160/100×b×b=8/5b×b
area of square= b×b
their ratio = 8/5b×b:b×b
= 8:5
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by @strange
let the breadth be b
length of rectangle=b+60%of b=160/100×b
area of rectangle=160/100×b×b=8/5b×b
area of square= b×b
their ratio = 8/5b×b:b×b
= 8:5
=============================
by @strange
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