Question

the length of a rectangle is 6cm more than three times its breadth the perimeter is 132 find its length​

Answer 1

Answer:

Length of rectangle be x and breadth be y

Perimeter = 2(x+y) = 132

given that x = 3y+6

perimeter,

132 = 2(3y+6+y)

132/2= 4y+6

66=4y+6

4y= 66-6

4y=60

y=15cm

x=3×15+6= 51cm

Answer 2

Answer:

Length of the rectangle  =  51cm

Step-by-step explanation:

Given,

Length of the rectangle is 6cm more than its breadth

Perimeter of the rectangle = 132

To find,

The length of the rectangle

Recall the formula

The perimeter of the rectangle = 2(l+b), where 'l' is the length and 'b' is the breadth of the rectangle

Solution:

Since length of the rectangle is 6cm more than its breadth, we have

l = 3b+6 -------------------(1)

Since perimeter of the rectangle is 132

2(l+b) = 132

Substitute the value of 'l' from equation(1) we get,

2(3b+6+b) = 132

2(4b+6) = 132

4b+6 = 66

4b = 60

b = 60/4 = 15

b = 15cm

From equation (1)

l = 3b+6

= 3×15 + 6

= 45 +6

= 51

l = 51cm

∴ Length of the rectangle  =  51cm

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