Question

The length of a rectangle is 6m less than twice it’s breadth. It perimeter of rectangle is 54m. Find

the area of rectangle.

Please Answer fast. ​

Answer 1

Answer:

if the perimeter of the rectangle is 54m, find the length and breadth.

27 m=3B-6

Add 6 to each side.

11 m=B ANSWER 1:

The breadth is 11 meters

. L=2B-6 m=2(11 m)-6 m=22m-6m =16 m

ANSWER 2

The length is 16 meters

Answer 2

Step-by-step explanation:

Given: Perimeter of rectangle is 54m

Length of a rectangle= 2b-6. (b= breadth)

Solution: Perimeter of rectangle= 2×(l+b)

54= 2×(2b-6+b)

54= 2×(3b-6)

54= 6b-12

54+12= 6b

66= 6b

b= 66/6

b= 11m Therefore, Breadth is 11m

Length= 2b-6

substitute the value of Breadth in Length

= 2×11-6

= 22-6

= 16m

Therefore, Length is 16m

Now, Area of rectangle= l×b

We own length and breadth, substitute the value

Area of rectangle= 16×11

= 176m