Question

the length of a rectangle is 6m more than its breadth and perimeter of rectangle is128m. find the dimensions of the rectangle​

Answer 1

Answer:

29 and 35

Step-by-step explanation:

2{L+b) = 128

L+b = 64

b+6 + b = 64

2b = 58

b = 29

L= 64-29

35

Answer 2

Given :

• The length of Rectangle is 6 m more than its breadth.
• Perimeter of Rectangle is 128 m.

To Find :

• Dimensions of Rectangle.

Solution :

$\longmapsto\tt{Let\:Breadth\:be=x}$

As Given that Length of Rectangle is 6 m more than its breadth . So,

$\longmapsto\tt{Length=x+6}$

Using Formula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}$

Putting Values :

$\longmapsto\tt{128=2(x+6+x)}$

$\longmapsto\tt{\cancel\dfrac{128}{2}=2x+6}$

$\longmapsto\tt{64-6=2x}$

$\longmapsto\tt{58=2x}$

$\longmapsto\tt{x=\cancel\dfrac{58}{2}}$

$\longmapsto\tt\bf{x=29}$

Value of x is 29 ..

Therefore :

$\longmapsto\tt{Length\:of\:Rectangle=29+6}$

$\longmapsto\tt\bf{35\:m}$

$\longmapsto\tt\bf{Breadth\:of\:Rectangle=29\:m}$