Question

the length of a rectangle is 6m more than its width.the perimeter of the rectangle is 60m.find its length and breadth​

Answer 1

Answer:

length - 18 and width - 12

let the width of rectangle - x

then length of rectangle - x+6

perimeter of rectangle - 2(l+b)

60 = 2(x+6+x)

60 = 2(2x+6)

60 = 4x+12

60-12 = 4x

48 = 4x

x = 12

width = x = 12m

length = x+6 = 12+6 = 18m

Answer 2

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The Breadth is 12 m and Length is 18m.

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

The Length of Rectangle = 6m more than width (Breadth)

Perimeter of the Rectangle = 60m

To find :

The Length and Breadth (Width) of the Rectangle

Solution :

Consider the Breadth as x

Length = x + 6

★ Equation :

$\boxed{\sf{2(x + x + 6) = 60}}$

$\sf{\implies} \: 2(x + x + 6) = 60$

$\sf{\implies} \:2x + 2x + 12 = 60$

$\sf{\implies} \:4x = 60 - 12$

$\sf{\implies} \:4x = 48$

$\sf{\implies} \:x = \dfrac{48}{4}$

$\sf{\implies} \:x = 12$

Value of x + 6

$\sf{\implies} \:12 + 6$

$\sf{\implies} \:18$

$\therefore$ The Breadth is 12 m and Length is 18m.

$\rule{300}{1}$

$\mathfrak{\large{\underline{\underline{Verification :-}}}}$

$\sf{\implies} \:2(12 + 18) = 60$

$\sf{\implies} \:36 + 24 = 60$

$\sf{\implies} \:60 = 60$

$\therefore$ The Breadth is 12 m and Length is 18m.