Question

The length of a rectangle is 7 cm more than its breadth and its perimeter is 46 cm. Find the length of its diagonal.​

Answer 1

Answer:

Here is ur answer

Step-by-step explanation:

let the breadth be 'x'

then length = x+7

Perimeter of rectangle = 2(l+b)

46=2(x+7+x)

23=2x+7

2x=23-7

x=16/2

x=8

Breadth = 8cm

length = 15cm

Now to find the diagonal we use Pythagoras theorem -

H^2 = P^2 + B^2

H^2 = 64 + 225

H^2 = 289

H = √289

H= 17cm

And hence, the length of the diagonal is 17 cm.

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Answer 2

Answer:

Breadth = 8 cm

Length = 8 + 7 = 15 cm

Length of diagonal = 17 cm

Step-by-step explanation:

Let the breadth be 'b'

Length be 'b + 7'

Perimeter = 2( l + b ) = 46

2(l + b) = 46

(l + b) = 23

b + 7 + b = 23

2b + 7 = 23

2b = 16

b = 8

Breadth = 8

Length = 8 + 7 = 15

Length of the diagonal =

Hyp² = B² + Alt²

Hyp² = (15)² + (8)²

Hyp² = 225 + 64

Hyp² = 289

Hyp = √289 = 17