Question

The length of a rectangle is 7 cm more than its breadth? if the perimeter is 62 cm find the length and breadth
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Answer 1

Step-by-step explanation:

2(l+b)=p

let breadth be b length be (b+7)

now,2(b+7+b)=62

2(2b+7)=62

2b=62/2-7

2b=24

b=12

l=12+7=19

Answer 2

Answer :

›»› The length and the breadth of a rectangle is 19 cm and 12 cm respectively.

Given :

• The length of a rectangle is 7 cm more than its breadth.
• The perimeter of a rectangle is 62 cm.

To Find :

• The length and the breadth of a rectangle.

Solution :

Let us assume that, the breadth of a rectangle is "x cm".

As it is given that, the length of a rectangle is 7 cm more than its breadth.

→ Length = 7 + x cm.

As we know that

→ Perimeter of a rectangle = 2(l + b)

→ 62 = 2(7 + x + x)

→ 62 = 2(7 + 2x)

→ 62 = 2 * 7 + 2 * 2x

→ 62 = 14 + 2 * 2x

→ 62 = 14 + 4x

→ 62 - 14 = 4x

→ 48 = 4x

→ x = 48/4

→ x = 12

Therefore,

The length and the breadth of a rectangle will be,

• Breadth = x = 12 cm.
• Length = 7 + x = 7 + 12 = 19 cm.

Hence, the length and the breadth of a rectangle is 19 cm and 12 cm respectively.

Verification :

→ Perimeter of a rectangle = 2(l + b)

→ 62 = 2(19 + 12)

→ 62 = 2 * 19 + 2* 12

→ 62 = 38 + 2 * 12

→ 62 = 38 + 24

→ 62 = 62

Here, LHS = RHS

Hence Verified !