Question

The length of a rectangle is 7 cm more than its breadth. If the
perimeter is 62cm.Find the length and breadth.

Answer 1

Answer:

breadth= b

length= 7+b

perimeter of a rectangle = 2(l+b) = 62

2(b+7+b)=62

2b+7= 62/2

2b+7= 31

2b=31-7

2b= 24

b= 24/2

b= 12 cm

Step-by-step explanation:

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Answer 2

Answer:

• Length and breadth of the rectangle is 19 cm and 12 cm respectively.

Step-by-step explanation:

Given that:

• The length of a rectangle is 7 cm more than its breadth.
• Perimeter of the rectangle is 62 cm.

To Find:

• The length and breadth of the rectangle.

Let us assume:

• The breadth of the rectangle be x.

Then,

• The length of the rectangle will be (x + 7).

As we know that,

• Perimeter of rectangle = 2(length + breadth)

Substituting the values,

$\sf{\longmapsto62=2(x+x+7)}$

Opening the bracket,

$\sf{\longmapsto62=2x+2x+14}$

Solving further,

$\sf{\longmapsto62=4x+14}$

Transposing 14 from RHS to LHS and changing its sign,

$\sf{\longmapsto62-14=4x}$

Subtracting,

$\sf{\longmapsto48=4x}$

Transposing 4 from RHS to LHS and changing its sign,

$\sf{\longmapsto\dfrac{48}{4}=x}$

Dividing,

$\sf{\longmapsto12=x}$

$\bf{\longmapsto x=12}$

Hence,

• x = 12

Therefore,

• Breadth of the rectangle = x = 12 cm
• Length of the rectangle = x + 7 = 12 + 7 = 19 cm