THE LENGTH OF A RECTANGLE IS 7 M MORE THAN ITS BREADTH.IF ITS PERIMETER IS 50 M,FIND THE LENGTH AND BREADTH OF THE RECTANGLE.
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Let the length of the rectangle be x.
Let the breadth of the rectangle be y.
Given that length of the rectangle is 7m more than its breadth.
x = y + 7.
We know that perimeter of a rectangle = 2x + 2y.
Given that perimeter of a rectangle = 50m.
2x + 2y = 50
2(y + 7) + 2y = 50
2y + 14 + 2y = 50
4y + 14 = 50
4y = 50 - 14
4y = 36
y = 9.
If y = 9 then x = y + 7
= 9 + 7
= 16.
The length of the rectangle = 16m and breadth of the rectangle = 9m.
Hope this helps!
Let the breadth of the rectangle be y.
Given that length of the rectangle is 7m more than its breadth.
x = y + 7.
We know that perimeter of a rectangle = 2x + 2y.
Given that perimeter of a rectangle = 50m.
2x + 2y = 50
2(y + 7) + 2y = 50
2y + 14 + 2y = 50
4y + 14 = 50
4y = 50 - 14
4y = 36
y = 9.
If y = 9 then x = y + 7
= 9 + 7
= 16.
The length of the rectangle = 16m and breadth of the rectangle = 9m.
Hope this helps!
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