The length of a rectangle is 7m more than its breadth. If its perimeter is 50m, find the length and breadth of the rectangle.
Answers
Answered by
3
Let the breadth be b
Length of the rect = 7 + b
Perimeter of a rect = 50 m
2(l+b) = 50
2(7+b+b) = 50
2(7+2b) =50
14 + 4b =50
4b = 50-14
4b = 36
b = 9
therefore,
breadth = 9m and
length = 7+9 = 16m
hope it helps u
Length of the rect = 7 + b
Perimeter of a rect = 50 m
2(l+b) = 50
2(7+b+b) = 50
2(7+2b) =50
14 + 4b =50
4b = 50-14
4b = 36
b = 9
therefore,
breadth = 9m and
length = 7+9 = 16m
hope it helps u
Answered by
2
Heya friend,
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Let its breadth be (x) m. Then,
it's length = (x+7) m.
According to question,
Perimeter of a rectangle = 2(l+b)
=> 50 = 2(x+7+x)
=> 50 = 2(2x+7)
=> 50/2 = 2x+7
=> 25 = 2x+7
=> 25-7 = 2x
=> 18 = 2x
=> x = 18/2
=> x = 9
Hence, it's breadth = 9 m and
it's length = 9+7 = 16 m.
Thanks
With regards@
Tanisha
◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆
Let its breadth be (x) m. Then,
it's length = (x+7) m.
According to question,
Perimeter of a rectangle = 2(l+b)
=> 50 = 2(x+7+x)
=> 50 = 2(2x+7)
=> 50/2 = 2x+7
=> 25 = 2x+7
=> 25-7 = 2x
=> 18 = 2x
=> x = 18/2
=> x = 9
Hence, it's breadth = 9 m and
it's length = 9+7 = 16 m.
Thanks
With regards@
Tanisha
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