The length of a rectangle is 7m more than its width. The perimeter of the rectangle is 60m. What are the dimensions?
Answers
Answer:
Let's start with the basics:
A = L x W
The problem states L = 7 + W. Let's substitute this into the equation:
A = (7 + W) x W
Now let's substitute in the area and simplify.
60 = W2 +7W By combing the 60 on the other side, we have a quadratic equation we can solve.
W2 +7W - 60 = 0 This format tells us that we need a number that will multiple to give a negative 60 but
has factors that when added will equal 7. The only ones that will give this is a -5 and
+12.
(W-5)(W +12) = 0 Now we will solve and will come up with two solutions.
W = 5 and W = -12 Because we can't have a negative area, the second solution is disregarded.
Therefore, the W = 5.
The Width is 5.
The Length is 7 +5, which is 12.
As a way to check this answer, multiplying 5 and 12 gives 60, which is the area stated in the problem.
Answer:
Let's start with the basics:
A = L x W
The problem states L = 7 + W. Let's substitute this into the equation:
A = (7 + W) x W
Now let's substitute in the area and simplify.
60 = W2 +7W By combing the 60 on the other side, we have a quadratic equation we can solve.
W2 +7W - 60 = 0 This format tells us that we need a number that will multiple to give a negative 60 but
has factors that when added will equal 7. The only ones that will give this is a -5 and
+12.
(W-5)(W +12) = 0 Now we will solve and will come up with two solutions.
W = 5 and W = -12 Because we can't have a negative area, the second solution is disregarded.
Therefore, the W = 5.
The Width is 5.
The Length is 7 +5, which is 12.
As a way to check this answer, multiplying 5 and 12 gives 60, which is the area stated in the problem
if it works plz make me brainliest and follow me