The length of a rectangle is 8 centimetres more than its width.ifthe perimeter of the rectangle is 44 centimetre find the length and breadth of the rectangle
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l is length
b is breadth given that l=b+8
perimeter=2 x{l+b}=44
=2 x [b+b+8]=44 substituting for l
=2b +8 =22 cancelling 2
=2b=14
b=7
l=15
b is breadth given that l=b+8
perimeter=2 x{l+b}=44
=2 x [b+b+8]=44 substituting for l
=2b +8 =22 cancelling 2
=2b=14
b=7
l=15
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