Question

The length of a rectangle is 8 CM and each of its diagonal measures 10 CM. Find it breath?

Answer 1

$\huge\underline\mathrm\red{GivEn:-}$

⭐ The length of a rectangle is 8 CM.

⭐ its diagonal measures 10 CM.

$\huge\underline\mathrm\red{To\: Find:-}$

↪ What is its breadth = ?

$\huge\underline\mathrm\red{SoLutioN:-}$

Let the breadth of the rectangle be x cm

Using Pythagoras theorem

Hypotenuse²=base+perpendicular²

According to question :-

$\longrightarrow$${10}^{2} = {8}^{2} + {x}^{2}$

$\longrightarrow$$100 = 64 + {x}^{2}$

$\longrightarrow$${x}^{2} = 100 - 64$

$\longrightarrow$${x}^{2} = 36$

$\longrightarrow$$x = 6$

${\bold{\green{\bigstar{\fbox{Breadth = 6 cm}}}}}$

Thus, the breadth of rectangle is 6 cm

$\huge\underline\mathrm\red{ThAnKs...}$

Answer 2

Answer:

$\implies$ x = 6

The breadth of rectangle is 6cm.

$\large\underline\mathrm{Given:-}$

• The length of a rectangle is 8cm.
• It's diagonal measure 10cm.

$\large\underline\mathrm{To \: find}$

• What is its breadth = ?

$\large\underline\mathrm{Solution}$

Let the breadth of the rectangle be x cm.

using Pythagoras theorem.

$\implies$ h² = p² + b²

$\implies$ 10² = x² + 8²

$\implies$ x² = 10² - 8²

$\implies$ x² = 100 - 64

$\implies$ x² = 36

$\implies$ x = 6

Thus,

The breadth of rectangle is 6cm.