The length of a rectangle is 8 cm and each of its diagonals measures 10 cm find its breadth
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given,length = 8cm
one of the diagonal=10cm
let ,ABCD is a rectangle.
AC is the diagonal=10cm
in triangle ABC,
AB=8cm,AC=10cm
BC^2=AC^2-AB^2
BC^2=10^2-8^2
=100-64
=36
BC=√36
therefore,BC=6cm
Breadth=6cm
Hope this answer will help you
PLEASE MARK IT AS BRAINLIEST
one of the diagonal=10cm
let ,ABCD is a rectangle.
AC is the diagonal=10cm
in triangle ABC,
AB=8cm,AC=10cm
BC^2=AC^2-AB^2
BC^2=10^2-8^2
=100-64
=36
BC=√36
therefore,BC=6cm
Breadth=6cm
Hope this answer will help you
PLEASE MARK IT AS BRAINLIEST
Attachments:
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