Math, asked by joyvarghese43667, 6 months ago

The length of a rectangle is 8 cm and its
perimeter is 26 cm. What is its breadth? (3)​

Answers

Answered by bhoomikasanjeev2009
6

Answer:

Let breadth be x cm.

Let breadth be x cm.Length = x+3 cm

Let breadth be x cm.Length = x+3 cmPerimeter of rectangle = 26 cm

Let breadth be x cm.Length = x+3 cmPerimeter of rectangle = 26 cm2(l+b)=26

Let breadth be x cm.Length = x+3 cmPerimeter of rectangle = 26 cm2(l+b)=26x+3+x=13

Let breadth be x cm.Length = x+3 cmPerimeter of rectangle = 26 cm2(l+b)=26x+3+x=132x=10

Let breadth be x cm.Length = x+3 cmPerimeter of rectangle = 26 cm2(l+b)=26x+3+x=132x=10x=5

Let breadth be x cm.Length = x+3 cmPerimeter of rectangle = 26 cm2(l+b)=26x+3+x=132x=10x=5Therefore,

Let breadth be x cm.Length = x+3 cmPerimeter of rectangle = 26 cm2(l+b)=26x+3+x=132x=10x=5Therefore,Breadth = 5 cm

Let breadth be x cm.Length = x+3 cmPerimeter of rectangle = 26 cm2(l+b)=26x+3+x=132x=10x=5Therefore,Breadth = 5 cmLength = 8 cm

Answered by Nishant7z
0

Answer:

5

Step-by-step explanation:

We know that

Perimeter of Rectangle = 2(l+b)

Hence, 2(l+b) = 26

=> (l+b)=26/2

=> l+b=13

(if l=8 the to find b we will subtract length from l+b)

=> b=13-8

=> b=5

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