Question

the length of a rectangle is 8 cm more than its breadth if the perimeter of the rectangle is 40m , find the area of the rectangle​

Answer 1

Answer:

let x = the width and x + 8 equal the length; then

2x + 2(x + 8) = 80 cm

4x + 16 = 80

4x + 64

x = 16; so length = 24 and width = 16

area = length times width or 24 x 16 = 384 cm^2 if my mental math is correct.

Step-by-step explanation:

Answer 2

Topic

Mensuration

Given

The length of a rectangle is 8 cm more than its breadth if the perimeter of the rectangle is 40 m.

To Find

Area of the rectangles.

Formula to be Used

Rectangle's

• Perimeter = 2( l + b )

• Area = l × b

where

l = Length of rectangle

b = Breadth of rectangle

Solution

It is given that,

l = b + 8

Perimeter = 40 cm

2( l + b ) = 40 cm

2( b + 8 + b ) = 40 cm

2( 2b + 8 ) = 40 cm

2b + 8 = 20 cm

2b = 12 cm

b = 6 cm

then

l = b + 8

l = ( 6 + 8 ) cm = 14 cm

Now,

Area = l × b

Area = 14 cm × 6 cm

Area = 84 cm²

Answer

So, area of given rectangle is 84 cm².