The length of a rectangle is 8 cm more than its width if the perimeter of the rectangle is 44 cm.Find the dimension of th
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Answer:
Perimeter of rectangle = 2(l+b)
=] let, the width of rectangle be x
=] The length of rectangle is 8 + x units
=] perimeter = 2( x + 8 + x) = 2(2x+8)
=] 2(2x + 8) = 44
=] 2x = 22-8
=] x = 14/2
=] x = 7cm
=] length of rectangle = 7 + 8 = 15cm
=] Breadth of rectangle = 7cm
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Answer:
length=15,breadth=7
Explanation:2[(8+b)+b]=44
8+2b=22
2b=14
b=7
and lenght=8+b=8+7=15
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