Question

The length of a rectangle is 8 cm more than its width if the perimeter of the rectangle is 44 cm.Find the dimension of th

Answer 1

Answer:

Perimeter of rectangle = 2(l+b)

=] let, the width of rectangle be x

=] The length of rectangle is 8 + x units

=] perimeter = 2( x + 8 + x) = 2(2x+8)

=] 2(2x + 8) = 44

=] 2x = 22-8

=] x = 14/2

=] x = 7cm

=] length of rectangle = 7 + 8 = 15cm

=] Breadth of rectangle = 7cm

Answer 2

Answer:

length=15,breadth=7

Explanation:2[(8+b)+b]=44

8+2b=22

2b=14

b=7

and lenght=8+b=8+7=15