the length of a rectangle is 8 m less than thrice it's width if area of the rectangle is 1675 sq m them find the length and width of the rectangle
Answers
Answered by
22
Solution :
Let breadth of the rectangle( b ) = x m
length ( l ) = ( 3x - 8 ) m
Area = 1675 sq m ( given )
=> l × b = 1675
=> ( 3x - 8 ) x = 1675
=> 3x² - 8x - 1675 = 0
=> 3x² -75x + 67x - 1675 = 0
=> 3x( x - 25 ) + 67 ( x - 25 ) = 0
=> ( x - 25 )( 3x + 67 ) = 0
=> x - 25 = 0 or 3x + 67 = 0
=> x = 25 or 3x = -67
=> x = 25 or x = -67/3
x should not be negative .
Therefore ,
b = x = 25 m
l = ( 3x - 8 )
= 3 × 25 - 8
= 75 - 8
l = 67 m
••••
Let breadth of the rectangle( b ) = x m
length ( l ) = ( 3x - 8 ) m
Area = 1675 sq m ( given )
=> l × b = 1675
=> ( 3x - 8 ) x = 1675
=> 3x² - 8x - 1675 = 0
=> 3x² -75x + 67x - 1675 = 0
=> 3x( x - 25 ) + 67 ( x - 25 ) = 0
=> ( x - 25 )( 3x + 67 ) = 0
=> x - 25 = 0 or 3x + 67 = 0
=> x = 25 or 3x = -67
=> x = 25 or x = -67/3
x should not be negative .
Therefore ,
b = x = 25 m
l = ( 3x - 8 )
= 3 × 25 - 8
= 75 - 8
l = 67 m
••••
Similar questions