The length of a rectangle is 8 meters more than its breadth. The
Perimeter of the rectangle is 22 meters. Find its length and breadth.
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Let the length be L and breadth be B
Given, L=8+B
Area of the board, L×B=(8+B)×B
Given, If its length is increased by 7 cm and breadth is decreased by 4 cm, its area remains unchanged.
⇒(L+7)(B−4)=L×B
But L=8+B
⇒(8+B+7)(B−4)=(8+B)×B
⇒(15+B)(B−4)=(8+B)×B
⇒15B−60+B^2−4B=8B+B^2
3B=60
B=20 cm
So, Length =20+8=28 cm
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