Math, asked by itsdhanusha6041, 1 year ago

The length of a rectangle is 8Cm.more than its width if the perimeter of rectangle is 44cm find the length and breat of rectangle

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Answered by hcsatbir
1

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Answered by silentlover45
8

\underline\mathfrak{Given:-}

  • \: \: \: \: \: \: \: Perimeter \: \: of \: \: the \: \: rectangle \: \: is \: \: {44cm}
  • \: \: \: \: \: \: \: length \: \: of \: \: the \: \: rectangle \: \: is  \: \: {8cm}

\underline\mathfrak{To \: \: Find:-}

  • \: \: \: \: \: find \: \: the \: \: length \: \: and \: \: width \: \: of \: \: the \: \: rectangle \: ?

\underline\mathfrak{Solutions:-}

  • \: \: \: \: \: \: \: Let \: \: the \: \: width \: \: be \: \: x \: \: cm.
  • \: \: \: \: \: \: \: Let \: \: the \: \: length \: \: be \: \: {(x \: + \: {8})} \: \: cm.
  • \: \: \: \: \: \: \: perimeter \: \: of \: \: rectangle \: \: = \: \: {44} \: \: cm.

\: \: \: \: \: \: \: \therefore \: The \: \: perimeter \: \: of \: \: a \: \: rectangle \: \: \leadsto \: \: {2} \: {(l \: + \: w)}

\: \: \: \: \: \: \: \leadsto  \: \: {44} \: \: = \: \: {2} \: {({x} \: + \: {x} \: + \: {8})}

\: \: \: \: \: \: \: \leadsto  \: \: {44} \: \: = \: \: {2} \: {({2x} \: + \: {8})}

\: \: \: \: \: \: \: \leadsto  \: \: \frac{44}{2} \: \: = \: \: {2x} \: + \: {8}

\: \: \: \: \: \: \: \leadsto  \: \: {22} \: \: = \: \: {2x} \: + \: {8}

\: \: \: \: \: \: \: \leadsto  \: \: {22} \: - \: {8} \: \: = \: \: {2x}

\: \: \: \: \: \: \: \leadsto  \: \: {14} \: \: = \: \: {2x}

\: \: \: \: \: \: \: \leadsto  \: \: {x} \: \: = \: \: \frac{14}{2}

\: \: \: \: \: \: \: \leadsto  \: \: {x} \: \: = \: \: {7}

  • \: \: \: \: \: \: \: width \: \: \leadsto \: \: {7cm}

  • \: \: \: \: \: \: \: length \: \: \leadsto \: \: {x \: + \: {8}}

\: \: \: \: \: \: \: \leadsto \: \: {{7} \: + \: {8}}

\: \: \: \: \: \: \: \leadsto \: \: {15}

  •  Hence, \\ \: \: \: \: \: \: \: The \: \: width \: \: of \: \: the \: \: rectangle \: \: \leadsto \: \: {7cm}. \\ \: \: \: \: \: \: \: The \: \: length \: \: of \: \: the \: \: rectangle \: \: \leadsto \: \: {15cm}.

\underline\mathfrak{Important \: \: formula:-}

  • \: \: \: \: \: \: \: Area \: \: of \: \: rectangle \: \: {l} \: \times \: {w}
  • \: \: \: \: \: \: \: Perimeter \: \: of \: \: rectangle \: \: {2} \: {({l} \: + \: {w})}
  • \: \: \: \: \: \: \: Diagonal \: \: of \: \: rectangle \: \: \sqrt{{l}^{2} \: + \: {w}^{2}}

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