the length of a rectangle is 8m less than thrice its width .if area of the rectangle is 1675sq m then find the length and width of the rectangle
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perimeter of a rectangle is 2( length *width)
let the width be x,so length will be x+4
2(4+x+x)=16
2(4+2x)=16
4+2x=8
2x=8-4
2x=4
x=4/2
x=2
length= 4 + 2 = 26
width=2
area= length* width
=6*2
=12
let the width be x,so length will be x+4
2(4+x+x)=16
2(4+2x)=16
4+2x=8
2x=8-4
2x=4
x=4/2
x=2
length= 4 + 2 = 26
width=2
area= length* width
=6*2
=12
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