Question

the length of a rectangle is 8m more than its breadth if its perimeter is 128m, find its length , breadth and Area

Answer 1

Answer:

Question:-

the length of a rectangle is 8m more than its breadth if its perimeter is 128m, find its length , breadth and Area

Answer:-

The length of Rectangle is 36 m

The breadth of rectangle is 28 m

The area of Given rectangle is 1008 m².

To find:-

Length and breadth of rectangle

Area of rectangle

Solution:-

Let the breadth be x

Length = 8 + x

Perimeter = 128 m

$\boxed{ \large{ \mathfrak{perimeter = 2(l + b)}}}$

According to question,

$\large{ \tt: \implies \: \: \: \: \: 2(8 + x + x) = 128}$

$\begin{gathered} \large{ \tt: \implies \: \: \: \: \: 8 + 2x = \frac{128}{2} } \\ \end{gathered}:$

$\large{ \tt: \implies \: \: \: \: \: 8 + 2x = 64}$

$\large{ \tt: \implies \: \: \: \: \: 2x = 64 - 8}$

$\large{ \tt: \implies \: \: \: \: \: 2x = 56}$

$\large{ \tt: \implies \: \: \: \: \: x = 28}$

The breadth of rectangle is 28 m

Length = 8 + x = 28 + 8 = 36 m

$\large{ \boxed{ \mathfrak{area = l \times b}}}$

$\large{ \tt: \implies \: \: \: \: \: area = 28\times 36}$

$\large{ \tt: \implies \: \: \: \: \: area = 1008 \: {m}^{2} }$

The area of Given rectangle is 1008 m².

Answer 2

Answer:

Length = 36m, Breadth = 28m, ar. = 1008 m^2

Step-by-step explanation:

Let's take Breadth of Rectangle as 'x' m,

So, Length of the rectangle = (x+8) m.

Perimeter of rectangle = 128 = 2 (l+b).

i.e. 128 = 2 (8+x+x)

128 = 2 (8+2x)

128 = 16 + 4x

128-16 = 4x

112 = 4x

x = 112/4 = 28m

Now, x = breadth = 28 m.

Length = x + 8 = 28 + 8 = 36 m

Area of rectangle = L*B

i.e. area = 28*36 = 1008 m^2