Question

the length of a rectangle is 8m more than its breadth if its perimeter is 128m, find its length , breadth and Area

Answer 1

Answer:

Question:-

the length of a rectangle is 8m more than its breadth if its perimeter is 128m, find its length , breadth and Area

Answer:-

The length of Rectangle is 36 m

The breadth of rectangle is 28 m

The area of Given rectangle is 1008 m².

To find:-

Length and breadth of rectangle

Area of rectangle

Solution:-

Let the breadth be x

Length = 8 + x

Perimeter = 128 m

$\boxed{ \large{ \mathfrak{perimeter = 2(l + b)}}}$

According to question,

$\large{ \tt: \implies \: \: \: \: \: 2(8 + x + x) = 128}$

$\begin{gathered} \large{ \tt: \implies \: \: \: \: \: 8 + 2x = \frac{128}{2} } \\ \end{gathered}:$

$\large{ \tt: \implies \: \: \: \: \: 8 + 2x = 64}$

$\large{ \tt: \implies \: \: \: \: \: 2x = 64 - 8}$

$\large{ \tt: \implies \: \: \: \: \: 2x = 56}$

$\large{ \tt: \implies \: \: \: \: \: x = 28}$

The breadth of rectangle is 28 m

Length = 8 + x = 28 + 8 = 36 m

$\large{ \boxed{ \mathfrak{area = l \times b}}}$

$\large{ \tt: \implies \: \: \: \: \: area = 28\times 36}$

$\large{ \tt: \implies \: \: \: \: \: area = 1008 \: {m}^{2} }$

The area of Given rectangle is 1008 m².

Answer 2

Hey Mate!!

This is the answer

Let the breadth of the rectangle be x m

This length of the rectangle = x + 6 m

We know Perimeter = 2 (length + breadth)

128 = 2 (x + 6 + x)

128 = 2 (2x + 6)

128 = 4x + 12

4x + 12 = 128

4x = 128 - 12

4x = 116

x = 116/4

x = 29 m

The breadth of the rectangle is 29 m

The length x + 6 = 29 + 6 = 35 m

Answer : the length of rectangle is 35 m and breadth of the rectangle is 29 m

Hope it helps...

Bye