Question

the length of a rectangle is 8m more than its breadth if its perimeter is 128m, find its length , breadth and Area

Answer 1

Answer:

Question:-

the length of a rectangle is 8m more than its breadth if its perimeter is 128m, find its length , breadth and Area

Answer:-

The length of Rectangle is 36 m

The breadth of rectangle is 28 m

The area of Given rectangle is 1008 m².

To find:-

Length and breadth of rectangle

Area of rectangle

Solution:-

Let the breadth be x

Length = 8 + x

Perimeter = 128 m

$\boxed{ \large{ \mathfrak{perimeter = 2(l + b)}}}$

According to question,

$\large{ \tt: \implies \: \: \: \: \: 2(8 + x + x) = 128}$

$\begin{gathered} \large{ \tt: \implies \: \: \: \: \: 8 + 2x = \frac{128}{2} } \\ \end{gathered}:$

$\large{ \tt: \implies \: \: \: \: \: 8 + 2x = 64}$

$\large{ \tt: \implies \: \: \: \: \: 2x = 64 - 8}$

$\large{ \tt: \implies \: \: \: \: \: 2x = 56}$

$\large{ \tt: \implies \: \: \: \: \: x = 28}$

The breadth of rectangle is 28 m

Length = 8 + x = 28 + 8 = 36 m

$\large{ \boxed{ \mathfrak{area = l \times b}}}$

$\large{ \tt: \implies \: \: \: \: \: area = 28\times 36}$

$\large{ \tt: \implies \: \: \: \: \: area = 1008 \: {m}^{2} }$

The area of Given rectangle is 1008 m².

Answer 2

Answer :-

• Length of Rectangle = 36 m.

• Breadth of rectangle = 28 m.

• Area of rectangle = 1008 sq.m.

Explanation :-

Given :

• The length of a rectangle is 8m more than its breadth.

• Perimeter of Rectangle = 128 m.

To find :

• Length, breadth and Area of rectangle.

Solution :

Let the breadth be x.

So, Length will be x + 8.

We know that,

❖ Perimeter of Rectangle = 2(l + b).

According to question,

➙ 2(8 + x + x) = 128.

➙ 2(8 + 2x) = 128.

➙ 16 + 4x = 128.

➙ 4x = 128 - 16.

➙ 4x = 112.

➙ x = 112 ÷ 4.

➙ x = 28.

Therefore,

• Breadth of rectangle = 28 m.

• Length of Rectangle = 8 + x = 36 m.

Now, Let's Calculate Area.

❖ Area of Rectangle = l × b.

➙ Area of Rectangle = 28 × 36.

➙ Area of Rectangle = 1008 sq. m.

Therefore, Area of Rectangle is 1008 sq.m.