the length of a rectangle is 8m more than its breadth if its perimeter is 128m, find its length , breadth and Area
Answers
Answer:
Question:-
the length of a rectangle is 8m more than its breadth if its perimeter is 128m, find its length , breadth and Area
Answer:-
- The length of Rectangle is 36 m
- The breadth of rectangle is 28 m
- The area of Given rectangle is 1008 m².
To find:-
- Length and breadth of rectangle
- Area of rectangle
Solution:-
Let the breadth be x
Length = 8 + x
Perimeter = 128 m
Formula used:
Now:
The breadth of rectangle is 28 m
Length = 8 + x
= 28 + 8
= 36 m
Formula used:
Now:
The area of Given rectangle is 1008 m².
Ummm done ✔ ^_^
Answer:
- Length is 36 m & breadth is 28 cm
- Area is 1008 m².
Step-by-step explanation:
Solution:-
Let the breadth,b be x metre
then, the length,l will be = x + 8 metres
and it is given that the perimeter of the rectangle is 128 m
As we know that perimeter of rectangle is calculated as the twice sum of length & breadth.
• Perimeter = 2 (l+b)
Substitute the value we get
→ 128 = 2 (x+x+8)
→ 128/2 = 2x + 8
→ 64 = 2x +8
→ 64-8 = 2x
→ 2x = 56
→ x = 56/2
→ x = 28 m
Length of the rectangle is x +8 = 28+8 = 36 m
Breadth of the rectangle is 28 m.
Now, calculating the area of rectangle . Area of rectangle is calculated by the product of Length & breadth.
• Area of rectangle = l ×b
Substitute the value we get
→ Area of rectangle = 28×36
→ Area of rectangle = 1008m²
- Hence, the area of the rectangle is 1008m².