Question

The length of a rectangle is a toys side of a square and 6cm greater than the side of a square is the area of the triangle is 3 times area of the square find the dimensions of each​

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Let the side of a square=x cm

Let the side of a square=x cm=>length of the rectangle =2x cm

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cm

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2Area =x^2 Sq cm

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2Area =x^2 Sq cmArea of rectangle =length × breadth

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2Area =x^2 Sq cmArea of rectangle =length × breadthArea=(2x)(x+6)

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2Area =x^2 Sq cmArea of rectangle =length × breadthArea=(2x)(x+6)Area=2x^2+12x

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2Area =x^2 Sq cmArea of rectangle =length × breadthArea=(2x)(x+6)Area=2x^2+12xArea of rectangle=3×(Area of square)

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2Area =x^2 Sq cmArea of rectangle =length × breadthArea=(2x)(x+6)Area=2x^2+12xArea of rectangle=3×(Area of square)2x^2+12x=3x^2

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2Area =x^2 Sq cmArea of rectangle =length × breadthArea=(2x)(x+6)Area=2x^2+12xArea of rectangle=3×(Area of square)2x^2+12x=3x^2x^2-12x=0

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2Area =x^2 Sq cmArea of rectangle =length × breadthArea=(2x)(x+6)Area=2x^2+12xArea of rectangle=3×(Area of square)2x^2+12x=3x^2x^2-12x=0x (x-12)=0

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2Area =x^2 Sq cmArea of rectangle =length × breadthArea=(2x)(x+6)Area=2x^2+12xArea of rectangle=3×(Area of square)2x^2+12x=3x^2x^2-12x=0x (x-12)=0x=0 (or) x-12=0 =>x=12

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2Area =x^2 Sq cmArea of rectangle =length × breadthArea=(2x)(x+6)Area=2x^2+12xArea of rectangle=3×(Area of square)2x^2+12x=3x^2x^2-12x=0x (x-12)=0x=0 (or) x-12=0 =>x=12If x=0 it can't form a square. So, x=12

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2Area =x^2 Sq cmArea of rectangle =length × breadthArea=(2x)(x+6)Area=2x^2+12xArea of rectangle=3×(Area of square)2x^2+12x=3x^2x^2-12x=0x (x-12)=0x=0 (or) x-12=0 =>x=12If x=0 it can't form a square. So, x=12•°• Side of the square =12cm

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2Area =x^2 Sq cmArea of rectangle =length × breadthArea=(2x)(x+6)Area=2x^2+12xArea of rectangle=3×(Area of square)2x^2+12x=3x^2x^2-12x=0x (x-12)=0x=0 (or) x-12=0 =>x=12If x=0 it can't form a square. So, x=12•°• Side of the square =12cmLength of the rectangle = 24cm

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2Area =x^2 Sq cmArea of rectangle =length × breadthArea=(2x)(x+6)Area=2x^2+12xArea of rectangle=3×(Area of square)2x^2+12x=3x^2x^2-12x=0x (x-12)=0x=0 (or) x-12=0 =>x=12If x=0 it can't form a square. So, x=12•°• Side of the square =12cmLength of the rectangle = 24cmWidth of the rectangle = 12cm

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2Area =x^2 Sq cmArea of rectangle =length × breadthArea=(2x)(x+6)Area=2x^2+12xArea of rectangle=3×(Area of square)2x^2+12x=3x^2x^2-12x=0x (x-12)=0x=0 (or) x-12=0 =>x=12If x=0 it can't form a square. So, x=12•°• Side of the square =12cmLength of the rectangle = 24cmWidth of the rectangle = 12cmArea of the square = 144 Sqcm

Let the side of a square=x cm=>length of the rectangle =2x cmWidth of the rectangle =(x+6)cmArea of square=side^2Area =x^2 Sq cmArea of rectangle =length × breadthArea=(2x)(x+6)Area=2x^2+12xArea of rectangle=3×(Area of square)2x^2+12x=3x^2x^2-12x=0x (x-12)=0x=0 (or) x-12=0 =>x=12If x=0 it can't form a square. So, x=12•°• Side of the square =12cmLength of the rectangle = 24cmWidth of the rectangle = 12cmArea of the square = 144 Sqcm Area of rectangle = 288 Sqcm