Question

The length of a rectangle is four times it's width. The area of the rectangle is 1024 cm2.
Find:
(i) the width of the rectangle.
(ii) the length of the rectangle

Answer 1

Step-by-step explanation:

4x*x=1024

4x^2 =1024

x=1024/4=256sq.root=16(breadth)

4*x=4*16=64(length)

Answer 2

Answer:

The Length is 64 cm and Width is 16 cm.

Step-by-step explanation:

Given :

Length of the rectangle is 4 times its Breadth

Area of the rectangle = 1024 cm²

To find :

Width and length of the rectangle

Solution :

Let the -

• Width be as y
• Length be as 4y

★ Area = Length × Width

⇒ 1024 = 4y × y

⇒ 1024 = 4y²

⇒ y² = 1024/4

⇒ y² = 256

⇒ y = $\sf{\sqrt{256}}$

⇒ y = 16

Width of the rectangle = 16 cm

$\rule{300}{1.5}$

★ Value of 4y

⇒ 4(16)

⇒ 64

Length of the rectangle = 64 cm

$\therefore$ The Length is 64 cm and Width is 16 cm.