Math, asked by abhijeetpandey558, 11 months ago

The length of a rectangle is four times its breadth. If its breadth is 8 cm, find its
perimeter and area.​

Answers

Answered by aswinrkumar4
2

Answer:

Perimeter=80cm

Area=256sq.cm

Explanation: see the pic

Thanks.

Attachments:
Answered by Anonymous
6

 \huge \underline \mathbb {SOLUTION:-}

AnswEr:

  • The perimeter of the rectangle = 80 Cm
  • The area of the rectangle = 256 Cm²

Given:

  • The length of a rectangle is four times it breadth.
  • The breadth of the rectangle is 8 Cm.

Need To Find:

  • The perimeter of the rectangle = ?
  • The area of the rectangle = ?

ExPlanation:

In Case l:

Need To Find:

  • The perimeter of the rectangle = ?

➠ The length of the rectangle = 4 × b

➠ The length of the rectangle = 4 × 8

➠ The length of the rectangle = 32 Cm

  • Hence, length of the rectangle is 32 Cm.

Now Formula used here:

  • Perimeter of rectangle = 2 × (l + b)

Putting the values according to the given formula:

➠ Perimeter of the rectangle = 2 × 8 + 32

➠ Perimeter of rectangle = 2 × 40

➠ Perimeter of rectangle = 80 Cm

  • Hence, the perimeter of the rectangle is 80 Cm.

\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}

In Case II:

Need To Find:

  • The area of the rectangle = ?

Formula used here:

  • Area of rectangle = Length × Breadth

Putting the values according to the given formula:

➠ Area of rectangle = 8 × 32

➠ Area of rectangle = 256 Cm²

  • Hence, the area of the rectangle is 256 Cm².

\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}

What is Perimeter?

  • The length of the boundary of a closed figure is called the perimeter.

  • Perimeter of rectangle = 2 × (Length + Breadth)
  • Perimeter of a square = 4 × Side

What is Area?

  • The measure of the surface enclosed by a closed figure is called area.

  • Area of rectangle = Length × Breadth
  • Area of a square = Side × Side

\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}

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