The length of a rectangle is four times its width.If the perimeter is 50cm,then the length of the rectangle is
Answers
D I A G R A M :
Here, we are given that the length of a rectangle is four times its width and the perimeter of the rectangle is 50 cm. We have to calculate the length of the rectangle. We'll assume the width as a variable and will error the length in the terms of width. After that, by forming a linear equation and solving that equation we'll find the value of the variable and will find the length.
Let,
- Width = x cm
According to the given question,
» The length of a rectangle is four times its width.
Length = 4 × Width
Length = 4x
As we know that,
★ Perimeter of rectangle = 2( l + w )
- l denotes length
- w denotes width
Here, perimeter = 50 cm (Given).
→ 50 = 2( 4x + x )
→ 50 = 8x + 2x
→ 50 = 10x
→ = x
→ 5 = x
- Value of x is 5.
As per the question,
→ Length = 4x
Substituting the value of x :
→ Length = 4(5) cm
→ Length = 20 cm
Therefore, length of the rectangle is 20 cm.
More about rectangles :
- A rectangle is a quadrilateral having 4 sides, 4 angles and 4 vertices.
- Opposite sides of a rectangle are equal.
- Measure of interior angles of a rectangle is 90° each.
- Perimeter = 2(length + breadth)
- Area = Length × Breadth
Given :
- Length of Rectangle is 4 times than the width
- Perimeter of Rectangle is 50cm
To Find :
- Length of Rectangle
Solution :
✬ Here in the Question we are given that length of Rectangle is 4 times then the Breadth, so we will let the Breadth be y and Length be 4y. we know that Perimeter of rectangle is 2 (Length + Breadth) By putting values in the formula we can easily find the Length of the Rectangle
- Let Breadth be = y
- Let Length be = 4y
Perimeter of Rectangle = 2 (L + B)
⟼ 50 = 2 (4y + y)
⟼ 50 = 8y + 2y
⟼ 50 = 10y
⟼ y = 50/10
⟼ y = 5cm
Length of Rectangle
⟼ Length = 4y
⟼ Length = 4 × 5
⟼ Length = 20cm
∴ Length of Rectangle is 20cm