Question

The length of a rectangle is four timesits breadth and the perimeter of therectangle is 90 m. Find the dimension of the rectangle.​

Answer 1

Answer:

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Answer 2

Solution :

$\bf{\red{\underline{\bf{Given\::}}}}$

The length of a rectangle is four times it's breadth and the perimeter of the rectangle is 90 m.

$\bf{\red{\underline{\bf{To\:find\::}}}}$

The dimensions of the rectangle.

$\bf{\red{\underline{\bf{Explanation\::}}}}$

Let the breadth of rectangle be r m

Let the length of rectangle be 4r m

We know that formula of the perimeter of rectangle :

$\bf{\boxed{\bf{Perimeter=2(Length+Breadth)}}}}}$

A/q

$\longrightarrow\sf{2(4r+r)=90}\\\\\\\longrightarrow\sf{4r+r=\cancel{\dfrac{90}{2} }}\\\\\\\longrightarrow\sf{5r=45}\\\\\\\longrightarrow\sf{r=\cancel{\dfrac{45}{5} }}\\\\\\\longrightarrow\sf{\green{r=9\:m}}$

Thus;

The length of rectangle is 4r = (4 × 9) m = 36 m

The breadth of rectangle is r = 9 m

$\boxed{\begin{minipage}{6cm}\underline{Some\:formulas\:of\:rectangle\::}\\ \\ \sf{Area = Length \times breadth}\\ \\ \sf{Perimeter=2(Length+breadth)}\\ \\ \sf{Diagonal=\sqrt{(Length)^{2} +(breadth)^{2} } } \end{minipage}}$