Question

The length of a rectangle is greater than its width by 3m. If its area be 10 sq.
m, find the perimeter of the rectangle

Answer 1

Answer:

The length is 5m.

Step-by-step explanation:

Step 1 : Let x be the width

x + 3

Step 2 : Write the equation that satisfies the problem

A = lw

A = lw 10 = (x + 3) (x)

Step 3 : Solve

Multiplying (x + 3) And (x) is equals to x² + 3x

Rewrite as standard form and the inverse of 10

x² + 3x - 10 = 0

THEN FACTOR THE EQUATION

x² + 3x -10 = 0

(x - 2) (x + 5) = 0

x - 2 = 0 x + 5 = 0

x - 2 + 2 = 0 + 2 x + 5 - 5 = 0 -5

x = 2 x = - 5

We'll use x = 2 for measurement

Step 4 : Go back to the problem

If x = 2

Width = 2

Length = 2 + 3 = 5m

THEREFORE, the length is 5m

Hope it helped