Question

The length of a rectangle is greater than its width by 3m. If its area be 10 sq.
m, find the perimeter of the rectangle

Answer 1

Answer:

let breadth is x

then length will be x+3

area of rectangle = l×b

10m²= (x+3)(x)

10m²= x²+3x

x²+3x-10=0

x²+5x-2x-10=0

x(x+5)-2(x+5)=0

(x-2)(x+5)=0

x= 2, -5

breadth = 2

length = 5

perimeter of the rectangle= 2(l+b)

= 2(5+2)

=14 m

hope it will helpful ....

Answer 2

Answer:

14

Step-by-step explanation:

let breadth is x

then length will be x+3

area of rectangle = l×b

10m²= (x+3)(x)

10m²= x²+3x

x²+3x-10=0

x²+5x-2x-10=0

x(x+5)-2(x+5)=0

(x-2)(x+5)=0

x= 2, -5

breadth = 2

length = 5

perimeter of the rectangle= 2(l+b)

= 2(5+2)

=14 m