Question

The length of a rectangle is greater than the
bread by 3 cm. If the lingth is incres
a am and the breadth is reduced by
5 cm, the area remains the same
find the dimentsions of the rectangle
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Answer 1

Answer:

To solve for speed or rate use the formula for speed, s = d/t which means speed equals distance divided by time. To solve for time use the formula for time, t = d/s which means time equals distance divided by speed.

Answer 2

Answer:

$\huge\tt{Question :- ⬇}$

The length of a rectangle is greater than the bread by 3 cm. If the lingth is increase a am and the breadth is reduced by 5 cm, the area remains the same find the dimentsions of the rectangle.

Step-by-step explanation:

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Let the breadth of the rectangle be X cm

Then, the length of the rectangle be (x+3)cm

∴ Area of the rectangle =(x+3)×x cm^2

−−−−−(1)

Given that

Length is increased by 9=x+3+9=x+12cm

and, breadth is reduced by 3=x−3cm

Now,

Area of new rectangle (x+12)×(x−3)cm^2 −−−−−(2)

But in the given question we have given that the both area is same

then we can get

(x+3)×x=(x+12)×(x−3)

⇒x^2+3x=x^2+12x−3x−36

⇒6x=36

∴x=6

Now,from equation(1)

Area of the rectangle=(x+3) × X

=(6+3)6

=54cm^2

$\huge = > \tt \blue{54 {cm}^{2} }$

Hope it helpful...☃️

Happy new year❤️