the length of a rectangle is greater than the breadth by 3 CM if the length is increased by 9 centimetre and the breadth is reduced by 5 centimetre the area remains the same find the dimensions of the rectangle
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let the breadth of rectangle is x cm
then length=x+3 cm
now, length = x+3+9
breadth=x-5
area of rectangle 1=area of rectangle 2
l*b=l*b
(x+3)x=(x+12)x-5
x²+3x = x²-5x+12x-60
x²+3x=x²+7x-60
7x-3x = 60. (x²=x² ,will cancel out
4x=60
x= 15
so the breadth = 15cm
then length= x+3
=15+3
=18cm
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