Question

The length of a rectangle is greater than the breadth by 3 cm. If the length
increased by 9 cm and the breadth is reduced by 5 cm, the area remains the same
Find the dimensions of the rectangle.
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Answer 1

Step-by-step explanation:

breadht of rectangle be= x cm

then length of rectangle be= x+3 cm

area of rectangle =l×b

(x+3)x cm^2

new length of rectangle increased by 9cm x+3+9=x+12 cm

new breadth of rectangle reduced by 5cm=x-5 cm

area of rectangle l×b

(x+12)(x-5)cm

x^2+3x=x^2+7x-60

x^2 cancel out

then 7x-3x=60

4x=60

x=15cm

breadth of rectangle =15cm

length of rectangle =x+3

15+3

18cm Ans...

Answer 2

Answer:

let area be x

therefore length= X/b

breadth= x/l

area= X/b× X/l

lb/x^2