Question

. The length of a rectangle is greater than the breadth by 3 cm. If the length is
increased by 9 cm and the breadth is reduced by 5 cm, the area remains the same
Find the dimensions of the rectangle.​

Answer 1

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Given :-

Length of rectangle is greater than breadth by 3 cm.

Area remains same , after increasing & decreasing length and breadth by 9 and 5 cm.

To Find :-

Dimensions

Solution :-

Let the breadth be x and length be x + 3

As we know that

Area = Length × Breadth

Area = x × x + 3

Area = x² + 3

Now,

New length = x + 12 cm

New breadth decreased by 5 = x - 5

(x + 12) (x - 5) = x² + 3x

x(x - 5) + 12(x - 5) = x² + 3x

x² - 5x + 12x - 60 = x² + 3x

-5x + 12x - 60 = 3x

7x - 60 = 3x

7x - 3x = 60

4x = 60

x = 60/4

x = 15 cm

Now,

Breadth = 15 cm

Length = x + 3 = 15 + 3 = 18

Answer 2

꧁Brother/Sister, Your correct answer will be꧂☞︎︎︎☟︎︎︎

✍︎Let the Breadth be x cm

➪Then the Length will be (x+3) cm.

∴Area of the Rectangle = x(x+3) cm².-----------------Eq (1)

✎Given that the length is increased by 9cm = x + 3 + 9 = x + 12cm.

➽Area of the Rectangle = (x+12)(x-5).------------------Eq (2)

✎On Solving (1) and (2), we get☞︎︎︎☟︎︎︎

➪x(x+3) = (x+12)(x-5)

➪x² + 3x = x² + 7x - 60

➪4x = 60

∴x= 60÷4=15

✍︎∴Breadth = 15cm

✍︎∴Length = 15 + 3 = 18cm.

꧁Hopes so that it will help you,꧂

❤︎With Love❤︎

✌︎Thanking you, your one of the Brother of your 130 Crore Indian Brothers and Sisters.✌︎