Question

the length of a rectangle is greater than the breadth by 3 cm. if the length is increased by 9 CM and breadth is reduced by 5 cm , the area remains the same, find the dimension of the rectangle.​

Answer 1

Answer:

i don't know if this will help but i set it out like this:

Step-by-step explanation:

the breadth = x

the length = x+3

(x+3) + 9 x (x+5) = (x+3) x X

Answer 2

Answer:

Let the length of rectangle = x+3 cm

breadth of rectangle = x cm

Area of rectangle = (x+3)x cm²

New length of rectangle = x+3+9 = x+12 cm

New breadth of rectangle = x-5 cm

New area of rectangle = (x+12)(x-5) cm²

So,

(x+3)x = (x+12)(x-5)

x²+3x = x²-5x+12x-60

x²-x²+3x = 7x-60

3x-7x = -60

-4x = -60

x = -60 = 15

-4

Length = x+3 =15+3 =18 cm

Breadth = x =15 cm

HOPE IT HELP

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