Question

The length of a rectangle is greater than twice it's breadth by 1cm if it's breadth is doubled and length is decreased by 4 cm it's area remains the same find the dimensions

Answer 1

Answer:

l=8

b=3.5

Step-by-step explanation:

let length of rectangle be l

and breadth be b

according to question:

l=2b+1

and if...

breadth is doubled i.e. breadth = 2b

and length = l-4

then area remains same

(l×b)= (l×b)

(2b+1)×b = (2b+1-4)(2b)

2b^2+b = 4b^2-6b

2b^2=7b

b^2=3.5b

b^2/b=3.5

b = 3.5

l= 2b+1

l= 2×3.5 + 1

l= 8

HOPE it HELPS

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