the length of a rectangle is increase by 60% . by what per cent would the breadth be decrease to maintain the same area ??
Answers
Answered by
5
let x = the decimal equiv decrease of the width
:
Write an area equation
Original area = new area
L * W = 1.6L * xW
Divide both sides by LW
1 = 1.6 * x
divide both sides by 1.6
1%2F1.6 = x
x = .625,
new width = .625*old width, therefore
1 - .625 = .375 * 100 = 37.5 decrease in the width to have the same area.
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:
Write an area equation
Original area = new area
L * W = 1.6L * xW
Divide both sides by LW
1 = 1.6 * x
divide both sides by 1.6
1%2F1.6 = x
x = .625,
new width = .625*old width, therefore
1 - .625 = .375 * 100 = 37.5 decrease in the width to have the same area.
HOPE that it will help..........
Plz mark it as brainliest...
Answered by
3
37.5%
Explanation:
160/100L× x/100B = LB
SO
x =10000/160 = 62.5%
so decrease in breadth = 100- 62.5 = 37.5%
Explanation:
160/100L× x/100B = LB
SO
x =10000/160 = 62.5%
so decrease in breadth = 100- 62.5 = 37.5%
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