Question

The length of a rectangle is increased by 40% by what percent would the width have to be decreased to maintain the same area

Answer 1

L * B = LB
L= L+ 40/100*L
L= L+ 2/5 *L
L= 7L/5

7L/5*B =LB
B=LB*5/7L
B = 5/7 B

Percentage of decrease in B = 5/7B divided by B *100

=71.42 %

Decrease in percentage =100%-71.42%=28.58%

Answer 2

Answer:

Let initial length = L ,initial breadth =B

therefore initial area= L*B

Final length =L+(40/100)L=1.4 L

Final breadth=B-(30/100)B=0.7 B

Final area=0.98 L*B

therefore there is decrease in area

decrease in area=0.02 L*B

% decrease in area=(0.02L∗B)/(L∗B)∗100=2(0.02L∗B)/(L∗B)∗100=2%

Step-by-step explanation:

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