Math, asked by sandeepkumar54863, 1 year ago

The length of a rectangle is increased by 60%. By what perent would the width

have to be decreased to maintain the same area​

Answers

Answered by Haridasan
2

37.5% to be decreased to maintain the same area

Answered by Anonymous
6

\huge\mathfrak{Answer}

Let the length 100 metre and breadth be 100m, then

New length = 160m, new breadth = x,

 \sf \: Then \:  \:  \:  \:  \:  \:  \:  \: 160 \times x = 100 \times 100  \\ \\   \sf \implies \: x =  \frac{100 \times 100}{160}  \implies \: x =  \frac{125}{2}

 \therefore \:  \rm \: decrease \: in \: breadth \:  = 100 -  \frac{125}{2} \% \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \implies  \sf \: 37 \:  \frac{1}{2} \%

So the answer is 37 and 1/2 %

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