Question

the length of a rectangle is more than its breadth by 9 cm .if the length and breadth are each increased by 3 cm,the area of new rectangle will be 64cm square more than that of the given rectangle.then the length and breadth of the rectangle are?​

Answer 1

Answer:

l=16, b=4

Step-by-step explanation:

check photo for clear explanation

Answer 2

Answer:

• Length = 82/6 cm.
• Breadth = 28/6 cm.

Explanation:

Given,

Length of a rectangle is 9 more than its breadth.

Let's say breadth as x cm.

Then, length will be (x + 9) cm.

∴ Area of the rectangle :

= length × breadth

= x(x + 9)

= x² + 9x

Now,

If the length and breadth increased by 3cm.

Then,

• New length = (x + 9) + 3 = (x + 12) cm.
• New breadth = (x + 3) cm

So on,

New area = (x + 12)(x + 3)

According to the question

New area is 64cm² more than the original area i.e., x² + 9x

⇒ (x + 12)(x + 3) = x² + 9x + 64

⇒ x² + 15x + 36 = x² + 9x + 64

⇒ 15x + 36 = 9x + 64

⇒ 15x - 9x = 64 - 36

⇒ 6x = 28

⇒ x = 28/6

Hence, the dimensions of the rectangle are

• Length = x + 9 = 28/6 + 9 = 82/6 cm.
• Breadth = x = 28/6 cm