the length of a rectangle is more than Twist of its breadth if the perimeter of the rectangle is 2012. Find the delimitation of the rectangle
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Let breadth of rectangle be x units.
then, Length be 2x units.
ATQ,
Perimeter of rectangle=2012
2(l+b) = 2012
2(2x+x) = 2012
2(3x) = 2012
6x = 2012
x = 2012/6 = 335.33
breadth x = 335.33 units
length 2x = 335.33*2 = 670.66 units
then, Length be 2x units.
ATQ,
Perimeter of rectangle=2012
2(l+b) = 2012
2(2x+x) = 2012
2(3x) = 2012
6x = 2012
x = 2012/6 = 335.33
breadth x = 335.33 units
length 2x = 335.33*2 = 670.66 units
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