Math, asked by melinahope2004, 7 months ago

The length of a rectangle is one more than four times its width, if the perimeter of the rectangle is 62 meters, find the dimensions of the rectangle.

Answers

Answered by Anonymous
1

Answer:

width : x, length : 4x + 1, Given, perimeter = 62 m. Perimeter : 2 (L+W) = 62 m. hence, L+W = 31 m.

Answered by GujjarBoyy
3

Step-by-step explanation:

Let the dimensions of the rectangle be :

width : x, length : 4x + 1,

Given, perimeter = 62 m.

Perimeter : 2 (L+W) = 62 m.

hence, L+W = 31 m.

(4x + 1) + x = 31

5x = 31 - 1

x = 30/5 = 6.

Width : x = 6 m.

Length : 4x+ 1 = 24 + 1 = 25 m.

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