Question

The length of a rectangle is reduced by 30%. By what percent would the width have to be increased to maintain the original area?​

Answer 1

Step-by-step explanation:

सॉरी बट आई डोंट नो हाउ टू गेट

Answer 2

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→ 37.5 %

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Area of rectangle : l × b

The length is increased by 60% .

So, the new length .

$l + \frac{60 + l }{100}= \frac{8l}{5}$

Area :

→ $\frac{81}{5} \times b1$

decrease% in width

→ 3/8 × 100

→ 37.5%