Question

the length of a rectangle is three times its breadth and its perimeter is 56 metre find its length and breadth​

Answer 1

Let the length of the rectangle be x 

 Breadth  = 3x

Perimeter = 56 m 

2(l+b) = 56 m 

l+b = 28 m 

x+3x = 28 m 

4x = 80 m 

x = 21 m 

length = 21 m Breadth = 7 m 

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Answer 2

Question:-

The length of a rectangle is three times its breadth and its perimeter is 56 metre find its length and breadth ?

Given :-

Perimeter of the rectangle is 56 meters .

Solution :-

Here

• Let length be x meters

$\texttt{Breath\:=\:x/3}$

$\bold{:\longrightarrow\:Perimeter\:\:=\:\:56\:m}$

$\bold{:\longrightarrow\:2(l\:+\:b)\:=56\:m}$

$\bold{:\longrightarrow\:l\:+\:b\:=\:\frac{56}{2}}$

$\bold{:\longrightarrow\:l\:+\:b\:=\:28\:m}$

$\bold{:\longrightarrow\:x\:+\:\frac{x}{3}\:=\:28m}$

$\bold{:\longrightarrow\:4x\:=\:80\:m}$

$\bold{:\longrightarrow\:x\:=\:\frac{80}{4} }$

$\bold{:\longrightarrow\:x\:=\:21\:m}$

$\bigstar\:\:\texttt{Now\:put\:the\:values\:of\:x\:=\:21\:in\:length\:and\:breath}$

• Length = x =21 m

• Breath = x/3 = 21/3 = 7meters

Diagram of rectangle

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 21 m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 7 m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Note :-

SEE THE DIAGRAM IN THE WEB OR LOPTOP